OCPJP Simulation Test 94

94

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Question: What is the output of the following code?

  1 import java.util.function.*;

  2 import java.util.*;

  3 public class Printing {

  4   public static void main(String...args) {

  5     Supplier<Set<String>> s1 = HashSet::new;

  6     System.out.print(s1.get().add("xyz"));

  7     System.out.print(s1.get());

  8     Supplier<Map<Integer, String>> s2 = TreeMap::new;

  9     System.out.print(s2.get());}}

Choice:
A. program print nothing
B. [][]{}
C. [xyz][]{}
D. [xyz][xyz]{}
E. [][xyz]{}
F. true[]{}
G. code does not compile
H. code compiles but throw runtime exceptions.



Next Question

Answer: F

Explain: Supplier functional interface takes no parameter, returns an object of the defined type. Line 5 declared a Supplier returns an object of type Set<String>. HashSet::new and () -> new HashSet<String>() are method reference and corresponding lambda function. Line 9 defined a Supplier returns an object of type Map<Integer, String>. Supplier functional interface defined the method get(), which is used to get the object supplied by the supplier. An empty HashSet<Object> print a [], an empty HashMap<Integer, String> print a {}. At line 6, s1.get() returns an empty HashSet<String>, s1.get().add("xyz") added an element to the set, function Set's add() function returns true or false. At line 7, s1.get() returns another 2 empty HashSet<String>.

Study:  Use  the built-in interfaces included in the java.util.function package such as Predicate, Consumer, Function, and Supplier   

Create and use ArrayList, TreeSet, TreeMap, and ArrayDeque objects

Use method references with Streams